How do you factor $6 s^{2} - s - 5$ $6s^2 - s - 5$ ?

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How do you factor $6 s^{2} - s - 5$ $6s^2 - s - 5$ ?

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Answer 1 · 2017-06-08T01:08:43

This expression can be factored as:

$(6 s + 5) (s - 1)$ $(6s + 5)(s - 1)$

Answer 2 · 2017-06-08T01:10:16

$(6 s + 5) (s - 1)$ $(6s + 5)(s - 1)$

Explanation:

Given: $6 s^{2} - s - 5$ $6s^2 - s - 5$

To factor you need to find two numbers $x, y$ $x, y$ that multiply to $- 5$ $-5$ :

$- 5, 1 or - 1, 5$ $-5, 1 " or " -1, 5$

Possible solutions:
$(6 s + x) (s - y) or (6 s - x) (s + y)$ $(6s + x)(s - y) " or " (6s - x)(s + y)$

$(2 s + x) (3 s - y) or (2 s - x) (3 s + y)$ $(2s + x)(3s - y) " or " (2s -x)(3s + y)$

Let $x = - 5, y = 1 :$ $x = -5, y = 1:$
$(6 s - 5) (s - 1) = 6 s^{2} - 6 s - 5 s + 5 = 6 s^{2} - 11 s + 5$ $(6s -5)(s -1) = 6s^2 -6s -5s + 5 = 6s^2 -11s + 5 " "$ NO

$(6 s + 5) (s - 1) = 6 s^{2} - 6 s + 5 s - 5 = 6 s^{2} - s - 5$ $(6s +5)(s-1) = 6s^2 -6s +5s -5 = 6s^2 -s -5" "$ YES

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How do you factor $6 s^{2} - s - 5$ $6s^2 - s - 5$ ?

2 Answers

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