How do you factor $6v^2+66v+60$ ?

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Answer 1 · 2015-05-25T18:07:51

Two steps.

First, factor out what's multiplying all the terms, which is $6$ :

$6(v^2+11v+10)$

Second, we find the roots and turn them into factors. Let's use Bhaskara (we're solving only for the parenthesis, not the original).

$(-11+-sqrt(121-4(1)(10)))/2=(-11+-9)/2$
$=>$ $v_1=-10$ and $v_2=-1$ .

To turn them into factors, we must equal each to zero, as follows:

$(v+10)=0$ and $(v+1)=0$

Now, just rewrite it all:

$6(v+10)(v+1)$

How do you factor 6v^2+66v+606v^2+66v+60?