How do you factor #6x^2 - 18x + 12#?

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Answer 1 · 2015-06-10T20:07:51

#6x^2-18+12=6(x-1)(x-2)#

#6x^2-18+12#

Factor out the GCF #6#.

#6(x^2-3x+2)#

Factor #x^2-3x+2#.

Find two numbers that when added are equal to #-3#, and when multiplied are equal to #2#.

The numbers #-1# and #-2# fit the criteria.

#x^2-3x+2=(x-1)(x-2)#

#6x^2-18+12=6(x-1)(x-2)#