How do you factor $- 6 x^{2} - 23 x - 20$ $-6x^2-23x-20$ ?

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How do you factor $- 6 x^{2} - 23 x - 20$ $-6x^2-23x-20$ ?

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Answer 1 · 2018-04-27T09:23:41

$- (3 x + 4) (2 x + 5)$ $-(3x+4)(2x+5)$

Explanation:

$- 6 x^{2} - 23 x - 20$ $-6x^2-23x-20$

= $- (6 x^{2} + 23 x + 20)$ $-(6x^2+23x+20)$

= $- (3 x + 4) (2 x + 5)$ $-(3x+4)(2x+5)$

Answer 2 · 2018-04-27T09:35:23

$- (3 x + 4) (2 x + 5)$ $-(3x+4)(2x+5)$

Explanation:

$factor out - 1$ $color(blue)"factor out "-1$

$\Rightarrow - (6 x^{2} + 23 x + 20)$ $rArr-(6x^2+23x+20)$

$using the a-c method to factor the quadratic$ $"using the a-c method to factor the quadratic"$

$the factors of the product 6 \times 20 = 120$ $"the factors of the product "6xx20=120$

$which sum to + 23 are + 8 and + 15$ $"which sum to + 23 are + 8 and + 15"$

$split the middle term using these factors$ $"split the middle term using these factors"$

$6 x^{2} + 8 x + 15 x + 20 \leftarrow factor by grouping$ $6x^2+8x+15x+20larrcolor(blue)"factor by grouping"$

$= 2 x (3 x + 4) + 5 (3 x + 4)$ $=color(red)(2x)(3x+4)color(red)(+5)(3x+4)$

$take out the common factor (3 x + 4)$ $"take out the "color(blue)"common factor "(3x+4)$

$= (3 x + 4) (2 x + 5)$ $=(3x+4)(color(red)(2x+5))$

$\Rightarrow 6 x^{2} + 23 x + 20 = (3 x + 4) (2 x + 5)$ $rArr6x^2+23x+20=(3x+4)(2x+5)$

$\Rightarrow - 6 x^{2} - 23 x - 20 = - (3 x + 4) (2 x + 5)$ $rArr-6x^2-23x-20=-(3x+4)(2x+5)$

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How do you factor $- 6 x^{2} - 23 x - 20$ $-6x^2-23x-20$ ?

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