How do you factor $6x^2=8x+8$ ?

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Answer 1 · 2018-04-21T18:57:10

The factored form is $(3x+2)(x-2)=0$ .

First, put everything on one side of the equation:

$6x^2=8x+8$

$6x^2-8x=8$

$6x^2-8x-8=0$

Factor out a $2$ :

$2(3x^2-4x-4)=0$

$2(3x^2-6x+2x-4)=0$

$2(3x(x-2)+2x-4)=0$

$2(3x(x-2)+2(x-2))=0$

$2(3x+2)(x-2)=0$

That's the factored polynomial. Hope this helped!

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