How do you factor $6x^2+99=49x$ ?

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Answer 1 · 2015-09-25T03:43:48

Factor 6x^2 + 99 = 49x

6x^2 - 49x + 99 = 0
D = b^2 - 4ac = 2401 + 2376 = 4777
This equation can't be factored because D is not a perfect square.

How do you factor 6x^2+99=49x6x^2+99=49x?