How do you factor $6x^6-3x^4-9x^2$ ?

Question

1623 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-07-26T14:18:14

$3x^2(2x^2-3)(x^2+1)$ .

The Expression $=6x^6-3x^4-9x^2$

$=3x^2(2x^4-x^2-3)$

Now, to factorise $=2x^4-x^2-3$ , let us put $x^2=t$ so that the

poly. will become,

$2t^2-t-3$

$=2t^2-3t+2t-3$

$=t(2t-3)+1(2t-3)$

$=(2t-3)(t+1)$

$=(2x^2-3)(x^2+1)$ ..................[ as, $t=x^2$ ]

Therefore, the Exp. $=3x^2(2x^2-3)(x^2+1)$ .

How do you factor 6x^6-3x^4-9x^26x^6-3x^4-9x^2?