How do you factor $6xy+12y-4x-8$ ?

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Answer 1 · 2016-12-23T15:04:16

The answer is $=(3y-2)(2x+4)$

Let's rewrite the equation

$6xy+12y-4x-8$

$=6xy-4x+12y-8$

$=2x(3y-2)+4(3y-2)$

$=(3y-2)(2x+4)$

How do you factor 6xy+12y-4x-86xy+12y-4x-8?