How do you factor $6 z^{2} + 12 z - a z - 2 a$ $6z^2+12z-az-2a$ ?

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Answer 1 · 2015-05-11T11:31:56

We can factor the expression by making groups of 2 terms:

$(6 z^{2} + 12 z) - (a z + 2 a)$ $(6z^2+12z)-(az+2a)$

$6 z$ $6z$ is a factor common to both the terms in the first group and
$a$ $a$ is a factor common to both the terms in the second group

We can write it as

$= 6 z (z + 2) - a (z + 2)$ $= 6z(z+2) - a(z+2)$

$z + 2$ $z+2$ is common to both the terms in the expression

$= (z + 2) (6 z - a)$ $= color(green)((z+2)(6z-a)$

How do you factor 6z^2+12z-az-2a6z2+12z−az−2a6z^2+12z-az-2a?