How do you factor $7 a^{2} - a b + 28 a - 4 b$ $7a^2-ab+28a-4b$ ?

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How do you factor $7 a^{2} - a b + 28 a - 4 b$ $7a^2-ab+28a-4b$ ?

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Answer 1 · 2016-04-28T22:22:26

There are 4 terms, so use the grouping method to create common factors.

Explanation:

$(7 a^{2} - a b) + (28 a - 4 b)$ $(7a^2 - ab) + (28a - 4b)$ Each bracket has a common factor.
= $a (7 a - b) + 4 (7 a - b)$ $a(7a-b) + 4(7a - b)$ This creates a common bracket.
= $(7 a - b) (a + 4)$ $(7a-b)(a+4)$

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How do you factor $7 a^{2} - a b + 28 a - 4 b$ $7a^2-ab+28a-4b$ ?

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How do you factor $7 a^{2} - a b + 28 a - 4 b$ $7a^2-ab+28a-4b$ ?