How do you factor $7 k (k - 3) + 4 (k - 3)$ $7k(k-3)+4(k-3)$ ?

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How do you factor $7 k (k - 3) + 4 (k - 3)$ $7k(k-3)+4(k-3)$ ?

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Answer 1 · 2015-07-21T22:13:00

$7 k (k - 3) + 4 (k - 3) = (7 k + 4) (k - 3)$ $7k(k-3) + 4(k-3) = (7k+4)(k-3)$

Explanation:

The factor $(k - 3)$ $color(blue)((k-3))$ occurs in both terms:
$XXXX$ $color(white)("XXXX")$ $7 k (k - 3)$ $color(red)(7k)color(blue)((k-3))$
$XXXX$ $color(white)("XXXX")$ and
$XXXX$ $color(white)("XXXX")$ $+ 4 (k - 3)$ $color(red)(+4)color(blue)((k-3))$

In general, the distributive property tells us that
$XXXX$ $color(white)("XXXX")$ $a (c) + b (c) = (a + b) (c)$ $color(red)(a)color(blue)((c))color(red)(+b)color(blue)((c)) = color(red)((a+b))color(blue)((c))$

So, in this case:
$XXXX$ $color(white)("XXXX")$ $7 k (k - 3) + 4 (k - 3) = (7 k + 4) (k - 3)$ $color(red)(7k)color(blue)((k-3))color(red)(+4)color(blue)((k-3)) = color(red)((7k+4))color(blue)((k-3))$

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How do you factor $7 k (k - 3) + 4 (k - 3)$ $7k(k-3)+4(k-3)$ ?

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Explanation:

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How do you factor 7k(k−3)+4(k−3)7k(k-3)+4(k-3)?

1 Answer

Explanation:

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How do you factor $7 k (k - 3) + 4 (k - 3)$ $7k(k-3)+4(k-3)$ ?