How do you factor $7x^2 -45$ ?

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Answer 1 · 2015-05-02T09:24:13

The answer is $(sqrt(7)x+sqrt(45))(sqrt(7)x−sqrt(45))$ .

$(7x^2-45)$ fits the pattern of the difference of squares in which $(a^2−b^2)=(a+b)(a−b)$ .

The factorization of $(7x^2-45)=((sqrt(7)x)^2−(sqrt(45))^2)$

Here $a=sqrt(7)x$ , $b=sqrt(45)$

So the factorization is $(sqrt(7)x+sqrt(45))(sqrt(7)x−sqrt(45))$

How do you factor 7x^2 -457x^2 -45?