How do you factor $7x^2 + 51x + 14$ ?

Question

3022 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-03-14T18:27:51

$(7x +2 ) (x +7)$ is the factorised form of the expression.

$7x^2 + 51x +14$

We can Split the Middle Term of this expression to factorise it.

In this technique, if we have to factorise an expression like $ax^2 + bx + c$ , we need to think of 2 numbers such that:

$N_1*N_2 = a*c = 7*14 = 98$

AND

$N_1 +N_2 = b = 51$

After trying out a few numbers we get $N_1 = 49$ and $N_2 =2$

$49 * 2 = 98$ , and $49 + 2= 51$

$7x^2 + 51x +14 =7x^2 + 49x +2x +14$

$=7x (x +7) + 2 (x+7)$

$=(7x +2 ) (x +7)$

$(7x +2 ) (x +7)$ is the factorised form of the expression.

How do you factor 7x^2 + 51x + 147x^2 + 51x + 14?