How do you factor $8 a b^{2} - 12 a b$ $8ab^2 -12ab$ ?

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Answer 1 · 2018-03-07T23:34:19

You factor both terms, and take common factors "out of the brackets". You leave the rest inside.

$= (2 \cdot 2 \cdot 2 \cdot a \cdot b \cdot b) - (2 \cdot 2 \cdot 3 \cdot a \cdot b)$ $=(2*2*2*a*b*b)-(2*2*3*a*b)$

Common is $= 2 \cdot 2 \cdot a \cdot b = 4 a b$ $=2*2*a*b=4ab$

$= 4 a b (2 b - 3)$ $=4ab(2b-3)$

How do you factor 8ab^2 -12ab8ab2−12ab8ab^2 -12ab?