How do you factor $8 k^{2} - 19 k + 9$ $8k^2-19k+9$ ?

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Answer 1 · 2016-07-14T15:56:39

not factorable

D = b^2 - 4ac = 361 - 288 = 73
Since D is not a perfect square, this trinomial can't be factored

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