Question

How do you factor `8w^2 - 18w + 9`?

Answer 1

Factor `y = 8x^2 - 18x + 9.`(1)

Ans: (4x - 3)(2x - 3)

Explanation:

`y = 8(x - p)(x - q)`
I use the new AC Method to factor trinomials.
Converted `y' = x^2 - 18x + 72 =`(x - p')(x - q')
Factor pairs of (-72) --> ...(4, 18)(6, 12) This sum is 18 = -b.
Then p' = -6 and q' = -12.
Back to equation (1): `p = (p')/a = -6/8 = -4/3` and `q = -12/8 = -3/2.`
Factored form: `y = 8(x - 3/4)(x - 3/2) = (4x - 3)(2x - 3)`