How do you factor $8x^2-17x+2$ ?

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Answer 1 · 2015-05-03T12:36:57

$8x^2-17x+2$

Look for integer factoring:
$"Factors (ignoring signs) of " 8 = {(1,8),(2,4)}$
$"Factors (ignoring signs) of " 2 ={(1,2)}$

Checking for a combination that adds up to $17$
quickly gives
$(8x-1)(x-2)$
as the required factors

How do you factor 8x^2-17x+28x^2-17x+2?