How do you factor $8x^3-125$ ?

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Answer 1 · 2018-03-24T18:34:34

$(2x-5)(4x^2+10x+25)$

Factoring difference of cubes ( $a^3-b^3$ ): $(a-b)(a^2+ab+b^2)$

Here, $a$ is $2x$ because the cube root of 8 is 2 and the cube root of $x^3$ is $x$ , $b$ is 5 because the cube root of 125 is 5.

Plug the numbers in:

$(2x-5)((2x)^2+2x*5+5^2)$

$(2x-5)(2^2x^2+10x+25)$

$(2x-5)(4x^2+10x+25)$

How do you factor 8x^3-1258x^3-125?