How do you factor $8 x^{3} + x^{2} + 56 x + 7$ $8x^3+x^2+56x+7$ ?

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How do you factor $8 x^{3} + x^{2} + 56 x + 7$ $8x^3+x^2+56x+7$ ?

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Answer 1 · 2018-04-18T02:04:35

the answer is $(x^{2} + 7) (8 x + 1)$ $(x^2+7)(8x+1)$

Explanation:

well since it's like this, all you have to do it group them since it's in a four term already. so: $(8 x^{3} + x^{2}) + (56 x + 7)$ $(8x^3+x^2)+(56x+7)$ and now take out from first equation $x^{2} (8 x + 1)$ $x^2(8x+1)$ and now the second $7 (8 x + 1)$ $7(8x+1)$ make sure the inside parenthesis matches and you got your answer

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How do you factor $8 x^{3} + x^{2} + 56 x + 7$ $8x^3+x^2+56x+7$ ?

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How do you factor $8 x^{3} + x^{2} + 56 x + 7$ $8x^3+x^2+56x+7$ ?