How do you factor $8z^2-64$ ?

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Answer 1 · 2017-03-29T01:30:07

See the entire solution process below:

$8$ is a common factor for both terms. Therefore, we can rewrite this expression as:

$8z^2 - 64 -> (8 * z^2) - (8 * 8) -> 8(z^2 - 8)$

If necessary we can further factor the term: $z^2 - 8$ .

We can use this rule to factor this term:

$a^2 - b^2 = (a + b)(a - b)$

We can let $a^2 = z^2$ therefore $a = z$

We can let $b^2 = 8$ therefore $b = sqrt(8)$

Substituting gives:

$8(z^2 - 8) = 8(z + sqrt(8))(z - sqrt(8)$

How do you factor 8z^2-648z^2-64?