How do you factor $9b^2-36$ ?

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Answer 1 · 2015-05-04T07:16:07

$9b^2 - 36$ can be written as $(3b)^2 - (6)^2$

this is of the form:

$a^2 - b^2 = ( a + b) (a -b )$

here: $a = 3b$ and $b = 6$

so ,

$(3b)^2 - (6)^2= (3b +6) (3b - 6)$

the factorized form of $9b^2 - 36$ is:

$(3b +6) (3b - 6)$

How do you factor 9b^2-369b^2-36?