How do you factor $9 c^{2} - 25 d^{4}$ $9c^2 - 25d^4$ ?

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Answer 1 · 2016-03-30T06:14:29

$9 c^{2} - 25 d^{4} = (3 c - 5 d^{2}) \cdot (3 c + 5 d^{2})$ $9c^2-25d^4=(3c-5d^2)*(3c+5d^2)$

$9 c^{2} - 25 d^{4} = {(3 c)}^{2} - {(5 d^{2})}^{2}$ $9c^2-25d^4=(3c)^2-(5d^2)^2$

$3 c = a$ $3c=a$
$5 d^{2} = b$ $5d^2=b$

${(3 c)}^{2} - {(5 d^{2})}^{2} = a^{2} - b^{2}$ $(3c)^2-(5d^2)^2=a^2-b^2$

$a^{2} - b^{2} = (a - b) \cdot (a + b)$ $a^2-b^2=(a-b)*(a+b)$

$9 c^{2} - 25 d^{4} = (3 c - 5 d^{2}) \cdot (3 c + 5 d^{2})$ $9c^2-25d^4=(3c-5d^2)*(3c+5d^2)$

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