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How do you factor $9 c^{2} + 6 c + 1$ $9c^2+6c+1$ ?

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Konstantinos Michailidis

Jun 8, 2016

Notice that $9 c^{2} + 6 c + 1 = {(3 c)}^{2} + 2 \cdot (3 c) + 1 = {(3 c + 1)}^{2}$ $9c^2+6c+1=(3c)^2+2*(3c)+1=(3c+1)^2$

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