How do you factor $9 g^{2} - 12 g + 4$ $9g^2-12g+4$ ?

Question

1899 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-08-13T17:24:12

$= (3 g - 2) (3 g - 2)$ $=(3g-2)(3g-2)$

$9 g^{2} - 12 g + 4$ $9g^2-12g+4$

$= 9 g^{2} - 6 g - 6 g + 4$ $=9g^2-6g-6g+4$

$= 3 g (3 g - 2) - 2 (3 g - 2)$ $=3g(3g-2)-2(3g-2)$

$= (3 g - 2) (3 g - 2))$ $=(3g-2)(3g-2))$

How do you factor 9g2−12g+49g^2-12g+4?