How do you factor $9 r^{2} - 35 r - 4$ $9r ^ { 2} - 35r - 4$ ?

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Answer 1 · 2018-03-16T02:11:33

$(9 x - 4) (x + 1)$ $(9x-4)(x+1)$

$9 r^{2} - 35 r - 4$ $9r^2-35r-4$

Factorise,

$(9 x - 4) (x + 1)$ $(9x-4)(x+1)$

How do you factor 9r2−35r−49r ^ { 2} - 35r - 4?