How do you factor $9t^3+66t^2-48t$ ?

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Answer 1 · 2017-08-08T02:12:04

See a solution process below:

First, we can factor a $3t$ out of each term in the expression giving:

$(3t * 3t^2) + (3t * 22t) - (3t * 16t) =>$

$3t(3t^2 + 22t - 16t)$

Next, we can factor the quadratic as:

$3t(3t - 2)(t + 8)$

How do you factor 9t^3+66t^2-48t9t^3+66t^2-48t?