How do you factor $9u^2+24uv+16v^2$ ?

Question

3080 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-07-22T09:26:50

$(3u+4v)^2$ .

Let us remember the Identity $: a^2+2ab+b^2=(a+b)^2$ .

Now, $9u^2+24uv+16v^2$

$=(3u)^2+2*3u*4v+(4v)^2$

$=(3u+4v)^2$ .

How do you factor 9u^2+24uv+16v^29u^2+24uv+16v^2?