How do you factor $9 x^{2} - 36 x + 24$ $9x^2 - 36x + 24$ ?

Question

How do you factor $9 x^{2} - 36 x + 24$ $9x^2 - 36x + 24$ ?

1 Answer

Impact of this question

1609 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-06-01T00:18:30

9(x - x1)(x - x2)

Explanation:

$f (x) = 3 y = 3 (3 x^{2} - 12 x + 8)$ $f(x) = 3y = 3(3x^2 - 12x + 8)$
Factor y, the trinomial in parentheses -->
$y = 3 x^{2} - 12 x + 8$ $y = 3x^2 - 12x + 8$
$D = b^{2} - 4 a c = 144 - 96 = 48$ $D = b^2 - 4ac = 144 - 96 = 48$ --> $d = \pm 4 \sqrt{3}$ $d = +-4sqrt3$
There are 2 real roots:
$x = - \frac{b}{2 a} \pm \frac{d}{2 a} = 2 \pm \frac{2 \sqrt{3}}{3}$ $x = -b/(2a) +- d/(2a) = 2 +- (2sqrt3)/3$
The 2 real roots are:
$x 1 = 2 + \frac{2 \sqrt{3}}{3}$ $x1 = 2 + (2sqrt3)/3$
$x 2 = 2 - \frac{2 \sqrt{3}}{3}$ $x2 = 2 - (2sqrt3)/3$
f(x) can be written in the factored form:

$f (x) = 3 y = 9 (x - x 1) (x - x 2) = = 9 (x - 2 + \frac{2 \sqrt{3}}{3}) (x - 2 - \frac{\sqrt{3}}{3})$ $f(x) = 3y = 9(x - x1)(x - x2) = = 9(x - 2 + (2sqrt3)/3)(x - 2 - (sqrt3)/3)$

Science

Math

Humanities

... and beyond

How do you factor $9 x^{2} - 36 x + 24$ $9x^2 - 36x + 24$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you factor 9x2−36x+249x^2 - 36x + 24?

1 Answer

Explanation:

Related questions

Impact of this question

How do you factor $9 x^{2} - 36 x + 24$ $9x^2 - 36x + 24$ ?