How do you factor #9x^3+36x^2-4x-16#? Algebra Polynomials and Factoring Factoring by Grouping 1 Answer Narad T. Jan 8, 2017 The answer is #=color(red)((x+4))color(blue)((3x+2)(3x-2))# Explanation: We use #a^2-b^2=(a+b)(a-b)# #9x^2-4=(3x+2)(3x-2)# Therefore, we start factorising #9x^3+36x^2-4x-16# #=9x^2color(red)((x+4))-4color(red)((x+4))# #=color(red)((x+4))color(blue)((9x^2-4))# #=color(red)((x+4))color(blue)((3x+2)(3x-2))# Answer link Related questions What is Factoring by Grouping? How do you factor by grouping four-term polynomials and trinomials? Why does factoring polynomials by grouping work? How do you factor #2x+2y+ax+ay#? How do you factor #3x^2+8x+4# by using the grouping method? How do you factor #6x^2-9x+10x-15#? How do you group and factor #4jk-8j^2+5k-10j#? What are the factors of #2m^3+3m^2+4m+6#? How do you factor quadratics by using the grouping method? How do you factor #x^4-2x^3+5x-10#? See all questions in Factoring by Grouping Impact of this question 4635 views around the world You can reuse this answer Creative Commons License