How do you factor 9x - 64x^39x64x3?

1 Answer
Aug 31, 2017

We have 9x - 64x^3 = f(x)9x64x3=f(x)

implies f(x) = x(9-64x^2)f(x)=x(964x2)
implies f(x) = x(3^2 - (8x)^2)f(x)=x(32(8x)2)
implies f(x) = x(3 + 8x)(3 - 8x)f(x)=x(3+8x)(38x)

And that's it.

9x - 64x^3 = x(3 + 8x)(3 - 8x)9x64x3=x(3+8x)(38x)