How do you factor 9x - 64x^39x−64x3? Algebra Polynomials and Factoring Factoring Completely 1 Answer Aritra G. Aug 31, 2017 We have 9x - 64x^3 = f(x)9x−64x3=f(x) implies f(x) = x(9-64x^2)⇒f(x)=x(9−64x2) implies f(x) = x(3^2 - (8x)^2)⇒f(x)=x(32−(8x)2) implies f(x) = x(3 + 8x)(3 - 8x)⇒f(x)=x(3+8x)(3−8x) And that's it. 9x - 64x^3 = x(3 + 8x)(3 - 8x)9x−64x3=x(3+8x)(3−8x) Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely 2x^2-82x2−8? Which method do you use to factor 3x(x-1)+4(x-1) 3x(x−1)+4(x−1)? What are the factors of 12x^3+12x^2+3x12x3+12x2+3x? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor 12c^2-7512c2−75 completely? How do you factor x^6-26x^3-27x6−26x3−27? How do you factor 100x^2+180x+81100x2+180x+81? See all questions in Factoring Completely Impact of this question 1634 views around the world You can reuse this answer Creative Commons License