How do you factor $9 x y^{2} - 16 x$ $9xy^2 - 16x$ ?

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Answer 1 · 2016-11-06T23:20:31

Please see the explanation for steps leading to the factors:

$x (3 y - 4) (3 y + 4)$ $x(3y - 4)(3y + 4)$

$9 x y^{2} - 16 x =$ $9xy^2 - 16x =$

$x (9 y^{2} - 16) =$ $x(9y^2 - 16) =$

$x (3 y - 4) (3 y + 4)$ $x(3y - 4)(3y + 4)$

How do you factor 9xy2−16x9xy^2 - 16x?