How do you factor $9 z^{2} + 27 z - a z - 3 a$ $9z^2 + 27z -az - 3a$ ?

Question

1542 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-05-08T06:20:03

We can factor this expression by making groups of 2 terms:

$(9 z^{2} + 27 z) - (a z + 3 a)$ $(9z^2 + 27z) -(az + 3a)$

$9 z$ $9z$ is common to both the terms in the first group, and $a$ $a$ is common to both the terms in the second group

$= 9 z (z + 3) - a (z + 3)$ $= 9z(z+3) - a(z+3)$

$z + 3$ $z+3$ is common to both the terms now

$= (z + 3) (9 z - a)$ $= color(green)((z+3)(9z-a)$

How do you factor 9z^2 + 27z -az - 3a9z2+27z−az−3a9z^2 + 27z -az - 3a?