How do you factor $a^{2} - 15 a + 56$ $a^2 - 15a + 56$ ?

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How do you factor $a^{2} - 15 a + 56$ $a^2 - 15a + 56$ ?

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Answer 1 · 2015-05-18T14:53:24

You find the root for the quadratic equation and transform them into factors, as follows:

Using Bhaskara:

$\frac{15 \pm \sqrt{225 - 224}}{2}$ $(15+-sqrt(225-224))/2$
$\frac{15 \pm 1}{2}$ $(15+-1)/2$
$a = 8$ $a=8$ and $a = 7$ $a=7$
These roots can be rewritten as factors:
$a - 8 = 0$ $a-8=0$ and $a - 7 = 0$ $a-7=0$

So, the final answer is

$(a - 8) (a - 7)$ $(a-8)(a-7)$

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How do you factor $a^{2} - 15 a + 56$ $a^2 - 15a + 56$ ?

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