How do you factor $a^2+4a+3$ ?

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Answer 1 · 2018-03-12T19:59:43

$(a+1)(a+3)$

$"using the a-c method of factoring"$

$"the factors of + 3 which sum to + 4 are + 1 and + 3"$

$rArra^2+4a+3=(a+1)(a+3)$

Answer 2 · 2018-03-12T20:01:12

$(a-1)(a+4) = 0$

We need to find two numbers that add to $4$ and multiply to $3$

$color(white)(.) + 4$
$color(white)(.) xx 3$
. . . . . . .
$1 xx 4$ $=> -1 + 4 = 3$

So our factors are $(a-1)(a+4) = 0$

$a = 1, -4$

How do you factor a^2+4a+3a^2+4a+3?