How do you factor $a (a + 6) + 7 (a + 6)$ $a(a+6)+7(a+6)$ ?

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Answer 1 · 2016-04-23T08:35:38

$a^{2} + 6 a + 7 a + 42$ $a^2 + 6a + 7a + 42$

$a^{2} + 13 a + 42$ $a^2 + 13a + 42$

First you need to expand out the brackets by multiplying the outer number with the inner two numbers separately. Now we'll do $a (a + 6)$ $a(a+6)$ .

$a \times a = a^{2}$ $a xx a = a^2$

$a \times 6 = 6 a$ $a xx 6 = 6a$

That's the first set of brackets expanded. Now for the second pair of brackets, where we do the same thing.

$7 \times a = 7 a$ $7 xx a = 7a$

$7 \times 6 = 42$ $7 xx 6 = 42$

Collect the like terms.

$7 a + 6 a = 13 a$ $7a + 6a = 13a$

Add the others.

$a^{2} + 13 a + 42$ $a^2 + 13a + 42$

You cannot solve this equation because the value of $a$ $a$ is unknown.

How do you factor a(a+6)+7(a+6) a(a+6)+7(a+6)?