How do you factor $a b - 3 a - 5 b + 15$ $ab - 3a - 5b + 15$ ?

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Answer 1 · 2015-05-23T03:33:12

$a b - 3 a - 5 b + 15 = (a - 5) (b - 3)$ $ab-3a-5b+15=(a-5)(b-3)$

Problem: Factor $a b - 3 a - 5 b + 15$ $ab-3a-5b+15$ .

Divide the terms into two groups.

$(a b - 3 a) - (5 b + 15)$ $(ab-3a)-(5b+15)$ =

$(a b - 3 a) - (5 b - 15)$ $(ab-3a)-(5b-15)$ =

Factor out the common terms in each group.

$a (b - 3) - 5 (b - 3)$ $a(b-3)-5(b-3)$

Factor out the common term $(b - 3)$ $(b-3)$ .

Solution: $a b - 3 a - 5 b + 15 = (a - 5) (b - 3)$ $ab-3a-5b+15=(a-5)(b-3)$

How do you factor ab−3a−5b+15ab - 3a - 5b + 15?