How do you factor $a c - 3 a d - 2 b c + 6 b d$ $ac - 3ad - 2bc + 6bd$ ?

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Answer 1 · 2018-04-27T13:28:04

$(a - 2 b) (c - 3 d)$ $(a-2b)(c-3d)$

$a c - 3 a d - 2 b c + 6 b d$ $ac-3ad-2bc+6bd$

Factorise $a$ $a$ out of the first two terms, and $- 2 b$ $-2b$ out of the last two terms,

$a (c - 3 d) - 2 b (c - 3 d)$ $a(c-3d)-2b(c-3d)$

Factorise $(c - 3 d)$ $(c-3d)$ from both terms,

$(a - 2 b) (c - 3 d)$ $(a-2b)(c-3d)$

Tadaaa :D

How do you factor ac - 3ad - 2bc + 6bdac−3ad−2bc+6bdac - 3ad - 2bc + 6bd?