How do you factor and solve $5c^3 - 45c = 0$ ?

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Answer 1 · 2015-05-24T17:28:31

We can see that $5c$ is multiplying both terms:

$5c(c^2-9)=0$

Thus, for this equation be true, either $5c$ and/or $(c^2-9)$ have to be equal to zero.

If $5c=0$ , then $c=0$ .

If $c^2-9=0$ , then $c^2=9$ and $c=+-3$

So, your answers are

$c_1=0$
$c_2=3$
$c_3=-3$

How do you factor and solve 5c^3 - 45c = 05c^3 - 45c = 0?