How do you factor $b^2-4b-60$ ?

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Answer 1 · 2018-05-20T15:04:11

$(b-10)(b+6)$

$b^2-4b-60$

find to numbers that their product is $-60$ and their sum is $-4$

which they are -10 and +6

so:

$(b-10)(b+6)$

to check multiply them together and you suppose to get the original equation back

$(b-10)*(b+6)$

$b^2+b6-10b-60$

$b^2-4b-60$

Answer 2 · 2018-05-20T15:07:42

$(b-10)(b+6)$

$"the factors of - 60 which sum to - 4 are - 10 and + 6"$

$rArrb^2-4b-60=(b-10)(b+6)$

How do you factor b^2-4b-60b^2-4b-60?