How do you factor $b^{3} + 6 b^{2}$ $b^3 + 6b^2$ ?

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Answer 1 · 2018-04-20T20:16:32

$b^{2} (b + 6)$ $b^2(b+6)$

Note that $b \times b \times b = b^{3}$ $bxxbxxb=b^3$
So $(b \times b) \times b \to b^{2} \times b = b^{3}$ $(bxxb)xxb->b^2xxb=b^3$

The 'thing' that is common to both 'parts' is $b^{2}$ $b^2$ in that we have:

$b^{2} b + 6 b^{2}$ $b^2b+6b^2$

Factor out the $b^{2}$ $b^2$ giving:

$b^{2} (b + 6)$ $b^2(b+6)$

How do you factor b3+6b2b^3 + 6b^2?