Question

How do you factor by grouping `3ax - 3bx - ay + by`?

Answer 1

`(a-b)(3x-y)`

Explanation:

`"consider the expression as two groups"`

`[3ax-3bx]+[-ay+by]`

`"factorise each 'group'"`

`color(red)(3x)(a-b)color(red)(-y)(a-b)`

`"take out the common factor "(a-b)`

`(a-b)(color(red)(3x-y))`

`rArr3ax-3bx-ay+by=(a-b)(3x-y)`