How do you factor by grouping $6x^3 - 2x + 3x^2 - 1$ ?

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Answer 1 · 2015-04-30T08:49:01

we are given, 6 $x^3$ $-$ 2 $x$ $+$ 3 $x^2$ $-$ 1

on rearrangement:

$=$ 6 $x^3$ $+$ 3 $x^2$ $-$ 2 $x$ $-$ 1

The first two terms have 3 $x^2$ in common and the last two terms have $-$ 1 in common:

taking out the common terms:

$=$ 3 $x^2$ ( $2x$ + 1) $-$ 1 ( 2 $x$ $+$ 1)

making groups of two:
$=$ (3 $x^2$ $-$ 1) ( $2x$ $+$ 1 )

How do you factor by grouping 6x^3 - 2x + 3x^2 - 16x^3 - 2x + 3x^2 - 1?