How do you factor by grouping $m^{4} + m^{3} - 12 m - 12$ $m^4+m^3-12m-12$ ?

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Answer 1 · 2015-05-02T09:37:55

You may notice that the first two have something in common, and so do the other two.

$= (m^{4} + m^{3}) + (- 12 m - 12)$ $=(m^4+m^3)+(-12m-12)$

So we take the common factors of both groups out of the brackets:

$= m^{3} (m + 1) - 12 (m + 1)$ $=m^3(m+1)-12(m+1)$ watch the signs!

Now we recombine:

$= (m^{3} - 12) (m + 1)$ $=(m^3-12)(m+1)$

How do you factor by grouping m4+m3−12m−12m^4+m^3-12m-12?