How do you factor by grouping #t^3-t^2+t-1#? Algebra Polynomials and Factoring Factoring by Grouping 1 Answer George C. May 10, 2015 #t^3-t^2+t-1 = (t^3-t^2)+(t-1) # #= t^2(t-1)+1(t-1)=(t^2+1)(t-1)#. Since #t^2+1 > 0# for all real values of #t#, there are no smaller factors with real coefficients. Answer link Related questions What is Factoring by Grouping? How do you factor by grouping four-term polynomials and trinomials? Why does factoring polynomials by grouping work? How do you factor #2x+2y+ax+ay#? How do you factor #3x^2+8x+4# by using the grouping method? How do you factor #6x^2-9x+10x-15#? How do you group and factor #4jk-8j^2+5k-10j#? What are the factors of #2m^3+3m^2+4m+6#? How do you factor quadratics by using the grouping method? How do you factor #x^4-2x^3+5x-10#? See all questions in Factoring by Grouping Impact of this question 3189 views around the world You can reuse this answer Creative Commons License