How do you factor by grouping $x y + 4 x - 2 y - 8$ $xy+4x-2y-8$ ?

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How do you factor by grouping $x y + 4 x - 2 y - 8$ $xy+4x-2y-8$ ?

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Answer 1 · 2015-04-15T12:02:43

Try collecting $y$ $y$ between the first and third term and $4$ $4$ between the second and the fourth:
$y (x - 2) + 4 (x - 2) =$ $y(x-2)+4(x-2)=$ now collect $(x - 2)$ $(x-2)$ ;
$(x - 2) (y + 4)$ $(x-2)(y+4)$

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How do you factor by grouping $x y + 4 x - 2 y - 8$ $xy+4x-2y-8$ ?

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