How do you factor completely $14gh-18h$ ?

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Answer 1 · 2018-04-06T08:53:16

$14gh-18h=2h(7g-9)$

to factorise we will take out the hcf rof each like term

$14gh-18h$

$hcf(14,18)=2$

$14gh-18h=color(red)(2)(7gh-9h)$

there is only $1$ $g$ term

$hcf(h,h)=h$

$14gh-18h=2color(red)(h)(7g-9)$

$14gh-18h=2h(7g-9)$

How do you factor completely 14gh-18h14gh-18h?