How do you factor completely $25x^2 -y^4$ ?

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Answer 1 · 2016-07-21T09:13:44

$25x^2-y^4=(5x+y^2)(5x-y^2)$

As $25x^2-y^4$ is difference of two squares, to factorize it we can use the identity $a^2-b^2=(a+b)(a-b)$

Hence $25x^2-y^4=(5x)^2-(y^2)^2$

= $(5x+y^2)(5x-y^2)$

How do you factor completely 25x^2 -y^425x^2 -y^4?