How do you factor completely $2x^2+50y^2-20xy$ ?

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Answer 1 · 2016-08-28T15:38:05

$2x^2+50y^2-20xy = 2(x-5y)^2$

Separate out the common scalar factor $2$ , rearrange into stanard order and notice a perfect square trinomial...

$2x^2+50y^2-20xy$

$= 2(x^2-10xy+25y^2)$

$= 2(x^2-2(x)(5y)+(5y)^2)$

$= 2(x-5y)^2$

How do you factor completely 2x^2+50y^2-20xy2x^2+50y^2-20xy?