How do you factor completely $2x^2 + 8x + 8$ ?

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Answer 1 · 2018-05-19T03:38:08

$2(x+2)^2$

$2x^2+8x+8$ has a GCF 2 so factor that out first

$2(x^2+4x +4)$

now factor:

$2(x+2)(x+2)$

finally:

$2(x+2)^2$

Answer 2 · 2018-05-19T03:40:24

$color(indigo)(=> 2 * (x + 2)^2$

Given : $2x^2 + 8x + 8$

$=> 2 (x^2 + 4x + 4)$

$=> 2(x^2 + 2x + 2x + 4)$

$=>2 (x (x + 2) + 2 (x+ 2))$

$=> 2 * (x+2) * (x+2)$

$color(indigo)(=> 2 (x + 2)^2$

How do you factor completely 2x^2 + 8x + 8 2x^2 + 8x + 8?