How do you factor completely $32 a^{4} - 162 b^{4}$ $32a^4 - 162b^4$ ?

Question

How do you factor completely $32 a^{4} - 162 b^{4}$ $32a^4 - 162b^4$ ?

1 Answer

Impact of this question

2755 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-05-22T01:19:24

It is

$32 a^{4} - 162 b^{4} = 2 \cdot (16 a^{4} - 81 b^{4}) = 2 \cdot ({(2 a)}^{4} - {(3 b)}^{4}) = 2 \cdot ({(2 a)}^{2} - {(3 b)}^{2}) \cdot ({(2 a)}^{2} + {(3 b)}^{2}) = 2 \cdot (2 a - 3 b) \cdot (2 a + 3 b) \cdot ({(2 a)}^{2} + {(3 b)}^{2})$ $32a^4-162b^4=2*(16a^4-81b^4)= 2*((2a)^4-(3b)^4)=2*((2a)^2-(3b)^2)*((2a)^2+(3b)^2)= 2*(2a-3b)*(2a+3b)*((2a)^2+(3b)^2)$

Science

Math

Humanities

... and beyond

How do you factor completely $32 a^{4} - 162 b^{4}$ $32a^4 - 162b^4$ ?

1 Answer

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you factor completely 32a^4 - 162b^432a4−162b432a^4 - 162b^4?

1 Answer

Related questions

Impact of this question

How do you factor completely $32 a^{4} - 162 b^{4}$ $32a^4 - 162b^4$ ?